Comments on: What is the difference in energy between the two levels responsible for the ultraviolet emission line of the? http://london-lez.org/emission/what-is-the-difference-in-energy-between-the-two-levels-responsible-for-the-ultraviolet-emission-line-of-the Tue, 22 May 2012 03:57:13 +0000 http://wordpress.org/?v=2.7 hourly 1 By: ATorres http://london-lez.org/emission/what-is-the-difference-in-energy-between-the-two-levels-responsible-for-the-ultraviolet-emission-line-of-the/comment-page-1#comment-4347 ATorres Mon, 18 Jan 2010 18:44:59 +0000 http://london-lez.org/emission/what-is-the-difference-in-energy-between-the-two-levels-responsible-for-the-ultraviolet-emission-line-of-the#comment-4347 The energy difference between the 2 energy levels involved in the UV light emission of an atom or molecule is: Del(E) = h x f = (h x c) / l f would be the frequency in sec-1 (Hz), if given, but it can be calculated from f = (c / l) where h is Planck's constant = 6.62 x 10E-34 J.secs; c is the speed of light = 3 x 10E08 m/s; and l is the wavelength of the emitted light, in meters = 285.2 x 10E-09 m Del(E) = (6.62 x 10E-34 x 3.0 x 10E10) / (2.85 x 10E-07) ~ 6.97 x 10E-17 Joules<br><b>References : </b><br> The energy difference between the 2 energy levels involved in the UV light emission of an atom or

molecule is:

Del(E) = h x f = (h x c) / l

f would be the frequency in sec-1 (Hz), if given, but it can be calculated from f = (c / l)

where h is Planck’s constant = 6.62 x 10E-34 J.secs;

c is the speed of light = 3 x 10E08 m/s;

and l is the wavelength of the emitted light, in meters = 285.2 x 10E-09 m

Del(E) = (6.62 x 10E-34 x 3.0 x 10E10) / (2.85 x 10E-07) ~ 6.97 x 10E-17 Joules
References :

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